Question 142
In the figure, $ABCD$ is a rectangle.
The area of triangle $DEC$ is $9\ \text{cm}^2$ and $BE = \frac{2}{5} BC$.
What is the area of $ABCD$ in $\text{cm}^2$?
The area of triangle $DEC$ is $9\ \text{cm}^2$ and $BE = \frac{2}{5} BC$.
What is the area of $ABCD$ in $\text{cm}^2$?