Question 50
For any integer $n \ge 1$, show that
$$
\sum_{k=1}^{n} \frac{2^k}{\sqrt{k+0.5}} \le 2^{n+1}\sqrt{n+1} - \frac{4n^{3/2}}{3}.
$$
$$
\sum_{k=1}^{n} \frac{2^k}{\sqrt{k+0.5}} \le 2^{n+1}\sqrt{n+1} - \frac{4n^{3/2}}{3}.
$$
MathNet 2016-part-05 — 184 problems (EN–VI) Question 50
Math Olympiad Vault · MathNet 2016-part-05 — 184 problems (EN–VI)