MathNet 2016-part-04 — 184 problems (EN–VI) Question 47

Consider triangle $ABC$ with $m(\angle B) = 30^\circ$, $m(\angle C) = 15^\circ$ and $M$ the midpoint of the side $[BC]$. Let $N \in (BC)$ be such that $[NC] = [AB]$. Show that $[AN]$ is the bisector of the angle $MAC$.