Question 143
Let $a$ and $b$ be positive real numbers such that $a + b = 2$. Prove that
$$
\frac{a}{1 + b + b^2} + \frac{b}{1 + a + a^2} \ge \frac{2}{3}.
$$
$$
\frac{a}{1 + b + b^2} + \frac{b}{1 + a + a^2} \ge \frac{2}{3}.
$$
MathNet 2016-part-02 — 184 problems (EN–VI) Question 143
Math Olympiad Vault · MathNet 2016-part-02 — 184 problems (EN–VI)