2023 AMC 12A Question 19 - thichhoctoan.com

Question 19

What is the product of all the solutions to the equation $$
\begin{gathered} \log_{7x}2023\cdot\log_{289x}2023\\ {}=\log_{2023x}2023? \end{gathered}
$$

$(\log_{2023}7\cdot\log_{2023}289)^2$
$\log_{2023}7\cdot\log_{2023}289$
$1$
$\log_7 2023\cdot\log_{289}2023$
$(\log_7 2023\cdot\log_{289}2023)^2$