Question 9A square of area $2$ is inscribed in a square of area $3,$ creating four congruent triangles, as shown below. What is the ratio of the shorter leg to the longer leg in the shaded right triangle? $\dfrac{1}{5}$$\dfrac{1}{4}$$2-\sqrt{3}$$\sqrt{3}-\sqrt{2}$$\sqrt{2}-1$
