Question 21In the figure, $ABCD$ is a square of side length $1.$ The rectangles $JKHG$ and $EBCF$ are congruent. What is $BE?$ $\dfrac12(\sqrt{6} - 2)$$\dfrac14$$2 - \sqrt{3}$$\dfrac{\sqrt{3}}{6}$$1 - \dfrac{\sqrt{2}}{2}$
