Question 20In $\triangle BAC,$ $\angle BAC=40^\circ,$ $AB=10,$ and $AC=6.$ Points $D$ and $E$ lie on $\overline{AB}$ and $\overline{AC},$ respectively. What is the minimum possible value of $BE+DE+CD?$$6\sqrt3+3$$\dfrac{27}{2}$$8\sqrt3$$14$$3\sqrt3+9$