Question 16Trapezoid $ABCD$ has $AD \parallel BC,$ $BD = 1,$ $\angle DBA = 23^\circ,$ and $\angle BDC = 46^\circ.$ The ratio $BC : AD$ is $9 : 5.$ What is $CD?$$\dfrac{7}{9}$$\dfrac{4}{5}$$\dfrac{13}{15}$$\dfrac{8}{9}$$\dfrac{14}{15}$