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2000 AMC 12 Question 20

AMC12 · 2000 AMC 12

Question 20

If $x,$ $y,$ and $z$ are positive numbers satisfying $$
x + \frac{1}{y} = 4,
$$ $$
y + \frac{1}{z} = 1,
$$ and $$
z + \frac{1}{x} = \frac{7}{3},
$$ then what is $xyz?$
  1. $\dfrac{2}{3}$
  2. $1$
  3. $\dfrac{4}{3}$
  4. $2$
  5. $\dfrac{7}{3}$