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1998 AMC 12 Question 28

AMC12 · 1998 AMC 12

Question 28

In triangle $ABC,$ angle $C$ is a right angle and $CB\gt CA.$ Point $D$ is located on $\overline{BC}$ so that angle $CAD$ is twice angle $DAB.$ If $\frac{AC}{AD}=\frac{2}{3},$ then $\frac{CD}{BD}=\frac{m}{n},$ where $m$ and $n$ are relatively prime positive integers. Find $m+n.$
  1. $10$
  2. $14$
  3. $18$
  4. $22$
  5. $26$