Question 172
Determine all real numbers $a$ such that the equation
$$
x^2 - (5-a)x + a^2 - 11a - 46 = 0
$$
has two real solutions, one of which is less than $2$, and the other greater than $2$.
$$
x^2 - (5-a)x + a^2 - 11a - 46 = 0
$$
has two real solutions, one of which is less than $2$, and the other greater than $2$.