Câu hỏi 5Cho $S=\frac{\sqrt2-1}{\sqrt2}+\frac{\sqrt3-\sqrt2}{\sqrt6}+\ldots+\frac{\sqrt9-\sqrt8}{\sqrt{72}}$. Tính $S$. $\frac1{\sqrt2}$$\frac12$$\frac34$$\frac13$$\frac23$