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1991 AMC 12 Question 13

AMC12 · 1991 AMC 12

Question 13

Horses $X,$ $Y,$ and $Z$ are entered in a three-horse race in which ties are not possible. If the odds against $X$ winning are $3$-to-$1$ and the odds against $Y$ winning are $2$-to-$3,$ what are the odds against $Z$ winning? (By “odds against $H$ winning are $p$-to-$q$” we mean that the probability of $H$ winning the race is $\frac{q}{p+q}.$)
  1. $3$-to-$20$
  2. $5$-to-$6$
  3. $8$-to-$5$
  4. $17$-to-$3$
  5. $20$-to-$3$