Question 19A triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of lengths $3,$ $4,$ and $5.$ What is the area of the triangle?$6$$\frac{18}{\pi^2}$$\frac9{\pi^2}(\sqrt3-1)$$\frac9{\pi^2}(\sqrt3+1)$$\frac9{\pi^2}(\sqrt3+3)$