1989 AMC 12 Question 4

In the figure, $ABCD$ is an isosceles trapezoid with side lengths $AD=BC=5,$ $AB=4,$ and $DC=10.$ The point $C$ is on $\overline{DF}$ and $B$ is the midpoint of hypotenuse $\overline{DE}$ in the right triangle $DEF.$ Then $CF=$