Question 102
Let $ABC$ be a triangle with $\angle A = 18^{\circ}$, $\angle B = 36^{\circ}$. Let $M$ be the midpoint of $AB$, $D$ a point on ray $CM$ such that $AB = AD$; $E$ a point on ray $BC$ such that $AB = BE$, and $F$ a point on ray $AC$ such that $AB = AF$. Find $\angle FDE$.