Question 156
Which of the following functions is the derivative of the function $f(x)=\frac{1-2x}{\sqrt{2x}}$?
(A) $f'(x)=\frac{-\sqrt{2x}(2x-1)}{4x^2}$
(B) $f'(x)=\frac{-\sqrt{2x}(2x-1)}{8x^2}$
(C) $f'(x)=\frac{-\sqrt{2x}(2x+1)}{4x^2}$
(D) $f'(x)=\frac{-\sqrt{2x}(2x+1)}{8x^2}$
(E) $f'(x)=\frac{-\sqrt{2x}(1-2x)}{4x^2}$
(A) $f'(x)=\frac{-\sqrt{2x}(2x-1)}{4x^2}$
(B) $f'(x)=\frac{-\sqrt{2x}(2x-1)}{8x^2}$
(C) $f'(x)=\frac{-\sqrt{2x}(2x+1)}{4x^2}$
(D) $f'(x)=\frac{-\sqrt{2x}(2x+1)}{8x^2}$
(E) $f'(x)=\frac{-\sqrt{2x}(1-2x)}{4x^2}$