Question 151
Four positive numbers are in the ratio $1:2:3:4$. The sum of the squares of the smallest three numbers is $1$ less than the sum of the largest three numbers. At most how many such sets of numbers can we find?
(A) $0$
(B) $1$
(C) $2$
(D) $3$
(E) $4$
(A) $0$
(B) $1$
(C) $2$
(D) $3$
(E) $4$