Question 138
For real numbers $x$ and $y$, where $x \neq 0$, $y \notin \{-2, 0, 2\}$ and $x + y \neq 0$, simplify the expression:
$$
\frac{x y^{2018} + 2 x y^{2017}}{y^{2016} - 4 y^{2014}} \cdot \left(\left(\frac{x^{2}}{y^{3}} + x^{-1}\right) : \left(x y^{-2} - \frac{1}{y} + x^{-1}\right)\right) : \frac{(x-y)^{2} + 4 x y}{1 + \frac{y}{x}} - \frac{y^{2} + 2y}{y+2}
$$
$$
\frac{x y^{2018} + 2 x y^{2017}}{y^{2016} - 4 y^{2014}} \cdot \left(\left(\frac{x^{2}}{y^{3}} + x^{-1}\right) : \left(x y^{-2} - \frac{1}{y} + x^{-1}\right)\right) : \frac{(x-y)^{2} + 4 x y}{1 + \frac{y}{x}} - \frac{y^{2} + 2y}{y+2}
$$