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MathNet 2018-part-03 — 181 problems (EN–VI) Question 6

Math Olympiad Vault · MathNet 2018-part-03 — 181 problems (EN–VI)

Question 6

Find the number of nonnegative integers $k$, $0 \le k \le 2188$, such that $\binom{2188}{k}$ is divisible by $2188$.
(Note that the binomial coefficient is defined by $\binom{n}{r} = \frac{n!}{r!(n-r)!}$.)