Question 110
Find all positive integers $n$ such that the equation
$$
3a^2 - b^2 = 2018^n
$$
has a solution in integers $a$ and $b$.
$$
3a^2 - b^2 = 2018^n
$$
has a solution in integers $a$ and $b$.
Math Olympiad Vault · MathNet 2018-part-01 — 181 problems (EN–VI)