Question 28
Let $ABCD$ be a parallelogram. Construct a square $BDXY$ with no interior points in common with the triangle $ABD$ and a square $ACZW$ with no interior points in common with the triangle $ADC$.
Let $P$ and $Q$ be the centers of the squares $BDXY$ and $ACZW$ respectively. Prove that $AP = DQ$.
Let $P$ and $Q$ be the centers of the squares $BDXY$ and $ACZW$ respectively. Prove that $AP = DQ$.