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1981 AMC 12 Question 5

AMC12 · 1981 AMC 12

Question 5

In trapezoid $ABCD,$ sides $AB$ and $CD$ are parallel, and diagonal $BD$ and side $AD$ have equal length. If $\angle DCB=110^\circ$ and $\angle CBD=30^\circ,$ then $\angle ADB=$

Question illustration
  1. $80^\circ$
  2. $90^\circ$
  3. $100^\circ$
  4. $110^\circ$
  5. $120^\circ$