Question 30
In $\triangle ABC,$ $E$ is the midpoint of side $BC$ and $D$ is on side $AC.$ If the length of $AC$ is $1$ and $\angle BAC=60^\circ,$ $\angle ABC=100^\circ,$ $\angle ACB=20^\circ,$ and $\angle DEC=80^\circ,$ then the area of $\triangle ABC$ plus twice the area of $\triangle CDE$ equals
