Question 23
For integers $k$ and $n$ such that $1\le k\lt n,$ let $$
\binom nk=\frac{n!}{k!(n-k)!}.
$$ Then $\left(\frac{n-2k-1}{k+1}\right)\binom nk$ is an integer
\binom nk=\frac{n!}{k!(n-k)!}.
$$ Then $\left(\frac{n-2k-1}{k+1}\right)\binom nk$ is an integer