Question 18In the adjoining figure, $AB$ is tangent at $A$ to the circle with center $O;$ point $D$ is interior to the circle; and $DB$ intersects the circle at $C.$ If $BC=DC=3,$ $OD=2$ and $AB=6,$ then the radius of the circle is $3+\sqrt3$$\frac{15}{\pi}$$\frac92$$2\sqrt6$$\sqrt{22}$