Question 23In the adjoining figure $AB$ and $BC$ are adjacent sides of square $ABCD;$ $M$ is the midpoint of $AB;$ $N$ is the midpoint of $BC;$ and $AN$ and $CM$ intersect at $O.$ The ratio of the area of $AOCD$ to the area of $ABCD$ is $\frac56$$\frac34$$\frac23$$\frac{\sqrt3}{2}$$\frac{\sqrt3-1}{2}$