Question 25
In parallelogram $ABCD$ of the accompanying diagram, line $DP$ is drawn bisecting $BC$ at $N$ and meeting $AB$ (extended) at $P.$ From vertex $C,$ line $CQ$ is drawn bisecting side $AD$ at $M$ and meeting $AB$ (extended) at $Q.$ Lines $DP$ and $CQ$ meet at $O.$ If the area of parallelogram $ABCD$ is $k,$ then the area of triangle $QPO$ is equal to
