Question 1If $x\ne0$ or $4$ and $y\ne0$ or $6,$ then $\frac2x+\frac3y=\frac12$ is equivalent to$4x+3y=xy$$y=\frac{4x}{6-y}$$\frac{x}{2}+\frac{y}{3}=2$$\frac{4y}{y-6}=x$none of these