Question 16If $F(n)$ is a function such that $F(1)=F(2)=F(3)=1,$ and such that $$ F(n+1)=\frac{F(n)F(n-1)+1}{F(n-2)} $$ for $n\ge3,$ then $F(6)$ is equal to:$2$$3$$7$$11$$26$