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1969 AMC 12 Question 27

AMC12 · 1969 AMC 12

Question 27

A particle moves so that its speed for the second and subsequent miles varies inversely as the integral number of miles already traveled. For each subsequent mile the speed is constant. If the second mile is traversed in $2$ hours, then the time, in hours, needed to traverse the $n$th mile is:
  1. $\dfrac2{n-1}$
  2. $\dfrac{n-1}{2}$
  3. $\dfrac2n$
  4. $2n$
  5. $2(n-1)$