Question 33
If $ab\ne0$ and $|a|\ne|b|,$ the number of distinct values of $x$ satisfying the equation
$$
\begin{aligned} \frac{x-a}{b}+\frac{x-b}{a} &=\frac{b}{x-a}\\ &\quad+\frac{a}{x-b} \end{aligned}
$$
is:
$$
\begin{aligned} \frac{x-a}{b}+\frac{x-b}{a} &=\frac{b}{x-a}\\ &\quad+\frac{a}{x-b} \end{aligned}
$$
is: