Question 14The length of rectangle $ABCD$ is $5$ inches and its width is $3$ inches. Diagonal $AC$ is divided into three equal segments by points $E$ and $F.$ The area of triangle $BEF,$ expressed in square inches, is:$\dfrac32$$\dfrac53$$\dfrac52$$\dfrac13\sqrt{34}$$\dfrac13\sqrt{68}$