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1966 AMC 12 Question 1

AMC12 · 1966 AMC 12

Question 1

Given that the ratio of $3x-4$ to $y+15$ is constant, and $y=3$ when $x=2,$ then, when $y=12,$ $x$ equals:
  1. $\dfrac18$
  2. $\dfrac87$
  3. $\dfrac73$
  4. $\dfrac72$
  5. $8$