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1964 AMC 12 Question 40

AMC12 · 1964 AMC 12

Question 40

A watch loses $2\dfrac12$ minutes per day. It is set right at $1$ P.M. on March $15.$ Let $n$ be the positive correction, in minutes, to be added to the time shown by the watch at a given time. When the watch shows $9$ A.M. on March $21,$ $n$ equals:
  1. $14\dfrac{14}{23}$
  2. $14\dfrac1{14}$
  3. $13\dfrac{101}{115}$
  4. $13\dfrac{83}{115}$
  5. $13\dfrac{13}{23}$