Question 32In this figure the center of the circle is $O.$ $\overline{AB}\perp\overline{BC},$ $ADOE$ is a straight line, $\overline{AP}=\overline{AD},$ and $\overline{AB}$ has a length twice the radius. Then: $\overline{AP}^{\,2}=\overline{PB}\cdot\overline{AB}$$\overline{AP}\cdot\overline{DO}=\overline{PB}\cdot\overline{AD}$$\overline{AB}^{\,2}=\overline{AD}\cdot\overline{DE}$$\overline{AB}\cdot\overline{AD}=\overline{OB}\cdot\overline{AO}$none of these