Câu hỏi 6Tính tổng $\dfrac6{3\times9}+\dfrac6{9\times15}+\dfrac6{15\times21}+\cdots+\dfrac6{93\times99}+\dfrac6{99\times105}$.$\frac8{51}$$\frac{17}{70}$$\frac{17}{105}$$\frac{34}{105}$