1959 AMC 12 Question 21
AMC12 · 1959 AMC 12
If $p$ is the perimeter of an equilateral triangle inscribed in a circle, the area of the circle is:
$\dfrac{\pi p^2}{3}$
$\dfrac{\pi p^2}{9}$
$\dfrac{\pi p^2}{27}$
$\dfrac{\pi p^2}{81}$
$\dfrac{\pi p^2\sqrt3}{27}$