Question 16The expression $$ \frac{x^2-3x+2}{x^2-5x+6}\div \frac{x^2-5x+4}{x^2-7x+12}, $$ when simplified, is:$\dfrac{(x-1)(x-6)}{(x-3)(x-4)}$$\dfrac{x+3}{x-3}$$\dfrac{x+1}{x-1}$$1$$2$