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1959 AMC 12 Question 4

AMC12 · 1959 AMC 12

Question 4

If $78$ is divided into three parts which are proportional to $1,$ $\dfrac13,$ $\dfrac16,$ the middle part is:
  1. $9\dfrac13$
  2. $13$
  3. $17\dfrac13$
  4. $18\dfrac13$
  5. $26$