Question 34The numerator of a fraction is $6x+1,$ the denominator is $7-4x,$ and $x$ can have any value between $-2$ and $2,$ both included. The values of $x$ for which the numerator is greater than the denominator are:$\dfrac35\lt x\le2$$\dfrac35\le x\le2$$0\lt x\le2$$0\le x\le2$$-2\le x\le2$