MathNet 2019-part-06 — 184 problems (EN–VI) Question 84

In triangle $ABC$ $\angle B = 60^{\circ}$, $O$ is the circumcenter, and $L$ is the foot of an angle bisector of angle $B$. The circumcircle of triangle $BOL$ meets the circumcircle of $ABC$ at point $D \neq B$. Prove that $BD \perp AC$.