Question 12If $P=\dfrac{s}{(1+k)^n},$ then $n$ equals:$\dfrac{\log(\frac{s}{P})}{\log(1+k)}$$\log\dfrac{s}{P(1+k)}$$\log\dfrac{s-P}{1+k}$$\log\dfrac{s}{P}+\log(1+k)$$\dfrac{\log s}{\log(P(1+k))}$