Question 37In right triangle $ABC,$ $BC=5,$ $AC=12,$ and $AM=x;$ $MN\perp AC,$ $NP\perp BC;$ $N$ is on $\overline{AB}.$ If $y=MN+NP,$ one-half the perimeter of rectangle $MCPN,$ then: $y=\dfrac12(5+12)$$y=\dfrac{5x}{12}+\dfrac{12}{5}$$y=\dfrac{144-7x}{12}$$y=12$$y=\dfrac{5x}{12}+6$
