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1957 AMC 12 Question 18

AMC12 · 1957 AMC 12

Question 18

Circle $O$ has diameters $\overline{AB}$ and $\overline{CD}$ perpendicular to each other. $\overline{AM}$ is any chord intersecting $\overline{CD}$ at $P.$ Then $AP\cdot AM$ is equal to:

Question illustration
  1. $AO\cdot OB$
  2. $AO\cdot AB$
  3. $CP\cdot CD$
  4. $CP\cdot PD$
  5. $CO\cdot OP$