Question 32
Two positive integers $x$ and $y$ are such that:
$$
\frac{2010}{2011}\lt\frac{x}{y}\lt\frac{2011}{2012}
$$
Find the smallest possible value of the sum $x+y$.
$$
\frac{2010}{2011}\lt\frac{x}{y}\lt\frac{2011}{2012}
$$
Find the smallest possible value of the sum $x+y$.