Question 181
The angle $ADC$ of the parallelogram $ABCD$ equals $40^\circ$. The point $K$ is given such that the segments $AK$ and $BC$ intersect, $AK = BC$ and $\angle BAK = 80^\circ$. The point $L$ is given such that the segments $CL$ and $AD$ intersect, $CL = AB$ and $\angle BCL = 80^\circ$.
Find the angles of the triangle $BKL$.
Find the angles of the triangle $BKL$.