Question 35
In the right triangle shown the sum of the distances $\overline{BM}$ and $\overline{MA}$ is equal to the sum of the distances $\overline{BC}$ and $\overline{CA}.$ If $\overline{MB}=x,$ $\overline{CB}=h,$ and $\overline{CA}=d,$ then $x$ equals:
