Question 32The factors of $x^4+64$ are:$(x^2+8)^2$$(x^2+8)(x^2-8)$$(x^2+2x+4)(x^2-8x+16)$$(x^2-4x+8)(x^2-4x-8)$$(x^2-4x+8)(x^2+4x+8)$